Let the square side be a.
b = 45-20
b = 25°
c² = 2a²
c = √(2)a
Calculating a.
a² = 1²+(√(2)a)²-2*1*√(2)acos25
a² = 1+2a²-2.5634255282a
a²-2.5634255282a+1 = 0
It implies;
a = 2.08345 units.
Again, a is the side length of the square.
(1/sind) = (2.08345/sin25)
d = 11.703400178°
Therefore, the required angle theta is;
d+45
= 11.703400178+45
= 56.703400178°
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