Mathematics Question and Solution
tana = 16/8
a = atan(2)°
b² = 16²+8²
b = 8√(5) cm.
Let BC = c.
Therefore;
c+3c = b
4c = 8√(5)
c = 2√(5) units.
Again, c is BC.
AB = 3c
AB = 3*2√(5)
AB = 6√(5) cm.
d = 180-30-atan(2)
d = (150-atan(2))°
(8/sin(150-atan(2))) = (e/sin(atan(2)))
e = 7.1682956077 cm.
sin60 = f/7.1682956077
f = 6.2079260981 cm.
h = 16-f
h = 16-6.2079260981
h = 9.7920739019 cm.
h is length b.
cos(atan(2)) = 2√(5)/j
j = 10 cm.
k = 16-j
k = 6 cm.
k is length a.
It implies length a plus length b (a+b) exactly in decimal is;
6+9.7920739019
= 15.7920739019 cm.
