Mathematics Question and Solution
Let a be the radius of the inscribed circle.
Calculating a.
b = 3a units.
c = b+a
c = 4a units.
It implies;
3a²+4a²+5a = 3a*4a
7a²+5a = 12a²
5a² = 5a
a = 1 unit.
Again, a is the radius of the inscribed circle.
It implies;
b = 3a units.
And a = 1 unit.
b = 3*1
b = 3 units.
Therefore, the required length, x is;
x = ⅓(c)
And
c² = 2b²
c² = 2*3²
c² = 18
c = √(18)
c = 3√(2) units.
Therefore;
x = ⅓(3√(2))
x = √(2) units.
