Mathematics Question and Solution
Let the radius of inscribed blue semi circle be 2 units.
Therefore the radius of the inscribed blue quarter circle will be 2 units.
The length of the ascribed rectangle will be 4 units.
The width of the ascribed rectangle will be;
Let the width be x.
x²+2²=4²
x²=16-4
x = √(12)
x = 2√(3) units.
Area ascribed rectangle is!
4*2√(2)
= 8√(3) square units.
Area blue is;
Area quarter circle with radius 2 units + Area semi circle with radius 2 units.
= ¼(4π)+½(4π)
= π + 2π
= 3π square units.
Fraction Blue is;
3π ÷ 8√(3)
= √(3)π/8
= 11√(3)/28
