Notice!
Triangle ABC is equilateral.
Let AB be 1 unit.
a = 180-42-12
a = 126°
a is angle BDC.
(1/sin126) = (b/sin42)
b = 0.8270909153 units.
b is CD.
c² = 1+0.8270909153²-2*0.8270909153cos48
c = 0.759747123 units.
c is AD.
Therefore, the required angle, angle CAD is;
Let it be d.
(0.759747123/sin48) = (0.8270909153/sind)
d = 54°
Again, d is the required angle, angle CAD.
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