Mathematics Question and Solution
Let the diameter of the inscribed white semicircle be x.
Therefore the diameter of the ascribed semicircle is 2x.
Calculating x.
(3x/2)² = x²+36
(9x²/4)-x² = 36
(5x²/4) = 36
√(5)x = 12
x = ⅕(12√(5)) units.
Where x is the radius of the ascribed semicircle.
Radius of the inscribed white semicircle is;
½(x)
= ⅕(6√(5)) units.
Area Blue is;
π½(⅕(12√(5)))² - π½(⅕(6√(5)))²
= ½(π(⅕(108)))
= ⅕(54π) square units.
