Mathematics Question and Solution
Sir Mike Ambrose is the author of the question.
Area A exactly as a single fraction is;
Area sector with radius 2√(2) units and angle 60° - Area equilateral triangle with side 2√(2) units+ Area rectangle with length √(2) units and width √(2)tan15 unit.
= (60π*(2√(2))²/360) - (½(2√(2))²*sin60) + (√(2)*√(2) tan15)
= ⅓(4π) - 2√(3) + 2tan15
= ⅓(4π-6√(3)+6tan15) square units.
= ⅓*4(3-3√(3)+π) square units.
