a = 40+10
a = 50°
a is angle ACB.
b = 180-10-50
b = 120°
b is angle ADC.
(6/sin120) = (c/sin10)
c = 1.2030698654 units.
c is CD.
(6/sin120) = (d/sin50)
d = 5.3073115854 units.
d is AD.
e = 180-120
e = 60°
e is angle ADB.
f = 180-50-50
f = 80°
f is angle ABD.
The required length, x (BD) is;
(5.3073115854/sin80) = (x/sin40)
x = 3.4641016151 units.
Again, x is the required length, BD.
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