Mathematics Question and Solution
55+2(90)+270+a = 180(5-2)
a+505 = 540
540° is the sum of the interior angles of a pentagon.
It implies;
a = 540-505
a = 35°
tan55 = b/4
b = 5.712592027 cm.
c = b-4
c = 1.712592027 cm.
tan55 = 8/d
d = 5.6016603057 cm.
e = d-4
e = 1.6016603057 cm.
It implies, area ABCDE is;
Area triangle with height 4 cm and base 5.712592027 cm + Area trapezoid with parallel sides 4 cm and 1.712592027 cm respectively and height 1.6016603057 cm.
= ½*4*5.712592027+½*(4+1.712592027)*1.6016603057
= 16 cm²
