Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
15th January, 2024

a = 180-50-30

a = 100°

a is angle AED.


Let DE = 1 unit.


(1/sin30) = (b/sin100)

b = 1.969615506 units.

b is AD.


c = 180-80-50

c = 50°

c is angle CAD.


(1.969615506/sin80) = (d/sin50)

d = 1.5320888862 units.

d is CD.


CE = 1.5320888862-1

CE = 0.5320888862 units.


e = 180-50

e = 130°

e is angle ADB.


f² = 0.5320888862²+1.969615506²-2*1.969615506*0.5320888862cos130

f = 2.3472963553 units.

f is AB.


Therefore, calculating the required angle, angle BAD (angle x).


(2.3472963553/sin130) = (1.969615506/sing)

g = 40°

g is angle ABD.


It implies angle BAD (angle x) is;

x = 180-130-40

x = 10°

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