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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2352349

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Let the small inscribed square side be a. Let b be the side of the big inscribed square. It implies; b = 10-a Therefore; Calculating a. tan(90-75) = a/(10-a) a(1+tan15) = 10tan15 a = (10tan15)/(1+tan15) a = ⅓(15-5√(3)) cm. b = 10-⅓(15-5√(3)) b = ⅓(15+5√(3)) cm. Blue area is; a²+b² = (⅓(15-5√(3)))²+(⅓(15+5√(3)))² = ⅓(200) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2350127

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Sir Mike Ambrose is the author of the question. Area R exactly in its simplest decimal form is; Area triangle with height 4.54406194214 units and base 2sin(atan(2)) units. = ½*4.54406194214*2sin(atan(2)) = 4.54406194214*sin(atan(2)) = 4.06433255864 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2349713

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Let the radius of the inscribed circle be r. The square side is 8 cm. b = 8-r c = 2+r Therefore; (2+r)² = 2²+(8-r)² 4+4r+r² = 4+64-16r+r² 4r = 64-16r 20r = 64 5r = 16 r = (16/5) cm. Area circle is; πr² = 256π/25 cm² = 32.16990877276 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2344174

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Sir Mike Ambrose is the author of the question. Let the side let of the square be 2 units. Therefore; Area square is; 2² = 4 square units. It implies; Area R is; Area trapezoid with parallel sides 1 unit and 1.44948974279 unit, and height 2 unit - Area square with side 1 unit - Area triangle with base and height 1 unit respectively - Area sector with radius √(2) unit and angle 32.3335306935° - Area triangle with height √(2) unit and base 0.3178372452 unit = (½*2(1+1.44948974279)) - (1*1)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2342889

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a = ½(4√(6)-2√(6)) a = √(6) cm. tan60 = b/√(6) b = 3√(2). b is the height of the trapezoid. c² = (√(6))²+(3√(2))² c² = 6+18 c = √(24) c = 2√(6) cm. Or cos60 = √(6)/c c = √(6)/(½) c = 2√(6) cm. c is the forward and backward equal slant lengths of the trapezoid. d = 180-45-60 d = 75° e = 75+60 e = 135° tanf = 3√(2)/(3√(6)) f = 30° g = 180-135-30 g = 15° (4√(6)/sin15) = (h/sin30) h = 18.9282032303 cm. (4√(6)/sin15) = (j/sin135) j = 26.7685217196 cm. k = 60-30 k = 30° It implies; Area Bl...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2340486

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 Notice. 64 cm is the perimeter of the square. Therefore, calculate a, the side length of the square. a = ¼(64) a = 16 cm. b = 16-11.5 b = 4.5 cm. c = 16-10 c = 6 cm. It implies; Area purple-shaded region is; Area square with side 16 cm - Area triangle with height and base 16 cm and 4.5 cm respectively - Area triangle with height and base 16 cm and 6 cm respectively. = (16*16)-½(16*4.5)-½(16*6) = 256-36-48 = 256-84 = 172 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2338704

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3A = ¼(9*9)π Where; 3A is the sum of the inscribed three equal areas. ¼(9*9)π is the area of the ascribed quarter circle. It implies; 12A = 9*9π A = (27/4)π cm² A is an area of the three equal areas that are inscribed the quarter circle. Notice. r, radius of the quarter circle is 9 cm. Poo9 Calculating x. a = (9-x) cm. a is the radius of the inscribed quarter circle. It implies; ¼(9-x)²π = (27/4)π (9-x)² = 27 9-x = 3√(3) 9-3√(3) = x x = 3(3-√(3)) units. x = 3.8038475773 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2338089

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Let r be the radius of the inscribed green semi circle. Notice. The ascribed triangle is equilateral. Therefore; sin60 = r/(0.5*7) r = 0.5*7sin60 r = 3.0310889132 units. Again, r is the radius of the inscribed green semi circle. It implies, area green inscribed semi circle is; ½(πr²) = 0.5*3.0310889132²π = 14.4316912524 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2337958

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Notice. Rectangle width is 4 units. a = 4-1 a = 3 units. tanb = ½ b = atan(⅓)° c = 2b c = 2atan(⅓)° d = 90-c d = (90-2atan(⅓))° tan(½d) = 2/e tan(0.5(90-2atan(⅓))) = 2/e e = 2/tan(0.5(90-2atan(⅓))) e = 4 units. f = e+2 f = 4+2 f = 6 units. f is the length of the rectangle. It implies; Area Rectangle is; Length*Width = 6*4 = 24 square units.

We are smart and clever!

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!
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