a = 1+1.5
a = 2.5 units.
b²+1.5² = 2.5²
b² = 6.25-2.25
b = √(4)
b = 2 units.
Let c be the radius of the ascribed semi circle.
d = 1+2
d = 3 units.
e = (3-c) units.
f = 1.5+e
f =...
Let the base of the inscribed green triangle be a.
b = (8-a) units.
c² = a²+8²
c = √(a²+64) units.
It implies;
(8-a)+8 = √(a²+64)
(16-a)² = a²+64
256-32a+a² = a²+64
32a = 192
4a =...
Area Orange exactly in fraction is;
Area triangle with height. 7.87908624144 units and base 4.37727013143 units + Area triangle with side (38/9) units and 9.01335086564 units, and angle 53.01709...
Let MP be 2 units.
a² = 1²+1²
a = √(2) units.
2b² = 1²
b² = ½
b = ½√(2) units.
c = a+b
c = ½(3√(2)) units.
d² = 1²+(½√(2))²-2*1*½√(2)cos135
d = 1.5811388301 units.
Therefore, th...
Calculating yellow area.
a² = 5²+5²-2*5*5cos120
120° is the single interior angle of the regular hexagon.
a = 5√(3) units.
a = 8.6602540378 units.
tanb = a/(2.5)
b = atan(5√(3)/(5/2))
b...
Let the side length of the three congruent regular hexagon be 1 unit each.
Notice.
The inscribed green triangle is equilateral.
a² = 2-2cos120
120° is the single interior angle of one of...
Calculating angle x.
tana = 1/3
a = atan(1/3)°
b² = 3²+1²
b = √(10) units.
1 - c
√(10) - 6
Cross Multiply.
√(10)c = 6
c = ⅗√(10) units.
c = 1.8973665961 units.
d² = 3²+1.8973...
Let a be the side length of the inscribed red equilateral triangle.
It implies;
(5/sin120) = (2.5/sinb)
b = 25.6589062733°
c = 60-b
c = 34.3410937267°
Calculating a.
a² = 2.5²+5²-2...
Sir Mike Ambrose is the author of the question.
Let BC be 1 unit.
Therefore;
AB is 2 units.
Area small square is;
(⅓√(13))²
= (13/9) square units.
Area blue is;
Area trapezium w...
Let a be the base of the blue inscribed triangle.
b = 4-1-a
b = (3-a) units.
c² = 2(1)²
c = √(2) units.
d² = 2(4)²
d = 4√(2) units.
e = d-c
e = 3√(2) units.
f² = a²+4²
f = √(a²+...
