By OnlineEdumath   |  18th September, 2024
Let a be the side length of the square. b² = 13²+a² b = √(169+a²) units. c² = 2a² c = √(2)a units. d²+5² = a² d = √(a²-25) units. e = b-d e = (√(169+a²)-√(a²-25)) units. Calculat...
By OnlineEdumath   |  18th September, 2024
b = √(625-a²) units. c = √(a²-256) units. Where a is the diameter of the blue circle. Calculating a. b² = c²+9² √(625-a²)² = √(a²-256)²+9² 625-a² = a²-256+81 625-a² = a²-175 2a² = 8...
By OnlineEdumath   |  18th September, 2024
Calculating angle x. x = 180-½(360-100-160) x = 180-½(360-260) x = 180-½(100) x = 180-50 x = 130°
By OnlineEdumath   |  18th September, 2024
a² = 4²+1² a = √(17) units. a is the diameter of the circle. b = ½(a) b = 0.5√(17) units. b is the radius of the circle. Area circle is; π(b²) = π(0.5√(17))² = ¼(17π) square units....
By OnlineEdumath   |  17th September, 2024
a = 1+3 a = 4 cm² b² = 4 b = 2 cm. 0.5*2c = 1 c = unit. d² = 1²+2² d = √(5) units. It implies; √(5) - 1 1 - e Cross Multiply. e = 1/√(5) e = ⅕√(5) units. f = d+e f =...
By OnlineEdumath   |  17th September, 2024
Let the radius of the ascribed semi circle be 1 unit. a² = 2(1)² a = √(2) units. b = ½(a) b = 0.5√(2) units. b is AM = CM. c² = 1²+1²-2*1*1cos(0.5*90) c = 0.7653668647 units. c is CN....
By OnlineEdumath   |  17th September, 2024
Let the single side length of the green square be x. Therefore; x ~ √(9-x²) 2 ~ 3 Cross Multiply. 3x = 2√(9-x²) 9x² = 4(9-x²) 9x² = 36-4x² 13x² = 36 x² = 36/13 Therefore the area of...
By OnlineEdumath   |  17th September, 2024
Sir Mike Ambrose is the author of the question. Let the width of the rectangle be x and the length be y. Let the unknown inscribed length of the rectangle be z. Calculating z. √(74)²+√(58)...
By OnlineEdumath   |  17th September, 2024
r = 5√(145)/8 unit. Please, move the above question one time, right/left to review the solution. Thank you.
By OnlineEdumath   |  16th September, 2024
Let a be the radius of the circle. b = (a-1) units. 7² = a²+b²-2abcosc --- (1). 11² = a²+b²+2abcosc --- (2). At (1). 7² = a²+b²-2abcosc 2abcosc = a²+b²-49 --- (3). Substituting (...
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