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9 = 8-8cosa
8cosa = -1
a = acos(-1/8)
a = 97.18075578146°
Therefore;
a• = 180-a
a• = 180-97.18075578146
a• = 82.81924421854°
b = ½(180-82.81924421854)
b = 48.59037789073°
c = ½(48.59037789073)...
a = acos(3/5)
Where a is angle GCA.
tan(acos(3/5)) = b/3
b = 4 units.
Where b is AG.
c = atan(⅔)
Where c is angle GBE.
d = 180-acos(3/5)-atan(⅔)
d = 93.17983011986°
Where d is angle BEC.
(6/sin9...
Let the inscribed square side be a.
tan60 = a/b
a = √(3)b cm.
Where b is BS = CR
It implies;
b+√(3)b+b = 10
(2+√(3))b = 10
b = 10(2-√(3)) cm.
Therefore;
a = √(3)*10(2-√(3))
a = 10(2√(3)-3) cm.
a...
Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service.
We make teaching and learning Mathematics fun for learners, we expose the simplicit...
xy = 40 ------ (1).
b = 4+x-5
b = x-1
y(x-1) = 20 ------ (2).
At (1)
x = 40/y ------ (3).
Notice;
y is the length or base of the rectangle.
Substituting (3) in (2) to get y.
y((40/y)-1) = 2...
Screenshot of today's teaching and learning activities with arithmetical, super smart and clever Oghenevwarhe.
Oghenevwarhe is in year 8.
Educator: Mr. Daniel
Making a circle to ascribe A, B, C and E quadrilateral with the circumference of the circle cutting across A, B, C and E.
Therefore;
Angle ABC will be;
½(240) = 120°
Parallelogram ABCD height is;...
Let the inscribed square side be a.
tan60 = a/b
a = √(3)b cm.
Where b is BS = CR
It implies;
b+√(3)b+b = 10
(2+√(3))b = 10
b = 10(2-√(3)) cm.
Therefore;
a = √(3)*10(2-√(3))
a = 10(2√(3)-3) cm....
