Let AB be 4 units.
BC = 6 units.
Let a be the side length of the inscribed square.
Calculating a.
b² = 4²-a²
b = √(16-a²)
It implies;
a = √(16-a²)
6 = 4
Cross Multiply.
4a = 6√(16-a²)
2a = 3√(...
Sir Mike Ambrose is the author of the question.
Radius of the ascribed circle is 13 cm.
a = acos((2*13²-24²)/(2*13²))
a = 134.76027010392°
b = ½(a)
b = 67.38013505196°
c = 40°
d = b - c
d = 27....
Le the side of the regular hexagon be 1 unit.
cosa = 0.5/1
a = 60°
b = 60-36
b = 24°
c = 108-24
c = 84°
Therefore;
The required angle, x is;
½(180-84)
= ½(96)
= 48°
Sir Mike Ambrose is the author of the question.
Let the length of the rectangle be 2 units.
Length AB is:
√(2) units.
a² = 2+1-2√(2)cos75
a = √(4-√(3)) units.
(a) Let Alpha be x.
Calc...
Sir Mike Ambrose is the author of the question.
Let the side of the square be 1 unit.
Area square is;
1²
= 1 square unit.
1 = ½+¼-½(√(2))cosa
½(√(2))cosa = ¾-1
a = acos(-√(2)/4)
a = 110.70481105...
Let the side length of the regular decagon be 1 unit.
a = (180*8)/10
a = 144°
a is a interior angle of the regular decagon.
b = 144-120
b = 24°
c² = 2-2cos24
c = 0.41582338164 units.
d = ½(180-2...
11-2 = (x²/4)
x = √(36)
x = 6.
Calculating Ax, let it be a.
(Area Under the curve at x = a and x = 6)(1/(6-a)) = (19/3)
(30-(a³/12)-2a) = (114-19a)/3
360-a³-24a = 456-76a
a³-52a+96 =...
tan30 = 6/a
a = 6√(3) cm.
a = 10.39230484541 cm.
sin30 = 6/b
b = 12 cm.
cos15 = c/12
c = (3√(6)+3√(2)) cm.
c = 11.59110991547 cm.
d = 11.59110991547²+10.39230484541²-2*11.59110991547*10.392304845...
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Let the green and purple color regular triangle side be a.
b = √(4²+2²)
b = 2√(5) units.
c = 0.5b
c = √(5) units.
d = √(8²+4²)
d = 4√(5) units.
e = √(a²+(a/2)²)
e = √(5a²/4)
e = ½(√(5)a)
Calcul...
