By OnlineEdumath   |  10th July, 2023
Let the radius of the inscribed half circle be 1 unit. Area rectangle is; 2*1 = 2 square units. Calculating Shaded Area as a single fraction.. It is; ½(1*2) - 1² + ¼(1)²π - ((180-2atan(½))π*1²/...
By OnlineEdumath   |  9th July, 2023
Notice; ½(R) units is the radius of the inscribed half circle. Therefore; The length of the ascribed square is; 2*½(R) = R units. tana = (R/(0.5R) a = atan(2)° b = (180-2ata(2))...
By OnlineEdumath   |  9th July, 2023
Let the square side be 2 units. Calculating the radius of the yellow circle inscribed triangle BGE. Let it be x. (0.5)²+1 = a² a = ½√(5) units. a is EG = BG. x+2(½√(5))x = 1 (1+√(5))x = 1 x = 1/...
By OnlineEdumath   |  9th July, 2023
a = atan(6/12) a = 26.56505117708° a = Angle BAE. b = 45-26.56505117708 b = 18.43494882292° b = Angle CAE. d = ½√(2*12²) d = 6√(2) cm. d = half AC = radius of the circle. Let the centre of the ci...
By OnlineEdumath   |  9th July, 2023
Let the square side, x be 1 unit. sin67.5 = a/1 a = 0.92387953251 units. cos67.5 = b/1 b = 0.38268343237 units. c = 2b c = 0.76536686473 units. d² = 1²+1² d = √(2) units. sin67.5...
By OnlineEdumath   |  9th July, 2023
Let the radius of the semi circle be 1 unit. cos20 = a/2 a = 1.87938524157 units. cos20 = 1/b b = 1.06417777248 units. c = a-b c = 0.81520746909 unit. Where c is AB, the side of the square.  Ar...
By OnlineEdumath   |  8th July, 2023
Let the square side be 2 units. Notice; a+b = c --- (1). 2√(2) = c+a 2√(2)-a = c --- (2). a² = 2d² d = (a/√(2)) units. e = 2-d e = (2-(a/√(2))) units. b² = (2-(a/√(2)))²+(a/√(2))² b² = 4-(4a/√(...
By OnlineEdumath   |  8th July, 2023
Let the side of the regular pentagon be 1 unit. Calculating Area Red. a² = 1²+1²-2*1*1cos108 a = 1.61803398875 units. b = 108-36-60 b = 12° (c/sin12) = (1.61803398875/sin96) c = 0.33826121272 un...
By OnlineEdumath   |  8th July, 2023
Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicit...
By OnlineEdumath   |  8th July, 2023
a² = 15²+12²-2*12*15cos120 a = 23.43074902772 cm. Where a is the side length of the equilateral triangle ABC. (23.43074902772/sin120) = (12/sinb) b = 26.32950349168° c = 60-b c = 33.67049650832°...
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