By OnlineEdumath   |  17th October, 2024
Sir Mike Ambrose is the author of the question. AC = 12 cm. AB = 10 cm. Therefore Area red exactly in cm² is; Area triangle with two side (165/90) cm and √(61) cm, and angle atan(5/6)° =...
By OnlineEdumath   |  16th October, 2024
Calculating blue area (area inscribed half circle). 15² = 13²+14²-2*13*14cosa 364cosa = 140 a = 67.380135052° (15/sin67.380135052) = (13/sinb) b = 53.1301023542° c = 180-a-b c = 59.489...
By OnlineEdumath   |  16th October, 2024
a = ½(360-90) a = ½(270) a = 135° b² = 6²+(4√(2))²-2*6*4√(3)cos135 b = 2√(29) units. b = 10.7703296143 units. 2c² = b² 2c² = (2√(29))² 2c² = 4*29 c² = 58 c = √(58) units. c is the ra...
By OnlineEdumath   |  16th October, 2024
Calculating Area Yellow. Let a be the radius of the ascribed semi circle. b²+6² = a² b = √(a²-36) units. b is the radius of the inscribed half circle. Therefore, area yellow is; ½(a²)...
By OnlineEdumath   |  15th October, 2024
Let the side length of the regular hexagon be 1 unit. a = ⅙*180(6-2) a = 120°  a is the single interior angle of the regular hexagon. sin30 = b/1 b = ½ units. cos30 = c/1 c = ½√(3) uni...
By OnlineEdumath   |  15th October, 2024
Sir Mike Ambrose is the author of the question. a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.410...
By OnlineEdumath   |  15th October, 2024
Sir Mike Ambrose is the author of the question. a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.410...
By OnlineEdumath   |  15th October, 2024
Let the side length of the regular hexagon be 1 unit. Therefore; a = 1 unit. Calculating b. Cos30=a/c And a = 1 c = 1/cos30 c = ⅔√(3) units. Where c is the hypotenuse of the r...
By OnlineEdumath   |  15th October, 2024
Sir Mike Ambrose is the author of the question. Area Blue, in cm² to 1 d. p. is; Half area regular pentagon with side 12 cm - area triangle with height 6 cm and base 6tan24 cm - area triangle w...
By OnlineEdumath   |  14th October, 2024
Calculating yellow area. a = ½(10) a = 5 km. a is the radius of the inscribed circle. tanb = 5/10 b = atan(½)° c = 180-2b c = (180-2atan(½))° d² = 2(5²)-2(5²)cos(180-2atan(½)) d =...
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