Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
4th October, 2026

Calculating red area.


a²+7² = 25²

a² = 625-49

a = √(576)

a = 24 units.


sinb = 24/25

b = asin(24/25)°


c = 180-b

c = 180-asin(24/25)

c = 106.260204708°


sin(0.5*106.260204708) = (0.5*25)/d

d = 15 units.

d is each length of the congruent lengths.


e²+(0.5*24)² = 15²

e² = 225-144

e = √(81)

e = 9 units.


f = ½(25) units.

f is the radius of the ascribed half circle.


It implies the red area is;


Area half circle with radius ½(25) units - Area triangle with height and base 24 units and 7 units respectively - Area triangle with height and base, 9 units and 24 units respectively.


½(25/2)²π-½(7*24)-½(9*24)


= ⅛(625)π-84-108


= ⅛(625)π-192


= ⅛((625)π-1536) square units.


= 53.4369260617 square units.

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