Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
27th August, 2026

Calculating GH/HI.


Let 2 units be the side length of the regular pentagon.


Therefore, 1 unit is the radius of the circle.


a = ⅕*180(5-2)

a = 108°

a is the single interior angle of the regular pentagon.


b = 360-90-90-108

b = 180-108

b = 72°

b is angle DOH.


sinb = (HI)/(OD)

OD = 1 unit, radius of the circle.

sin72 = HI/1

HI = sin72 units.

HI = 0.9510565163 units.


Calculating GH.


c = 180-72

c = 108°

c is angle EOH.


d = 360-90-108-108

d = 270-216

d = 54°

d is angle EGH.


e = ½(180-108)

e = 36°

e is angle OEH equal angle OHE.


f = 90-e

f = 90-36

f = 54°

f is angle EHG.


Notice.


d = f = 54°


It implies;


g² = 1²+1²-2*1*1cos108

g = √(2-2cos108)

g = 1.61803398875 units.

g is EH equal EG.


h = 108-e

h = 108-36

h = 72°

h is angle GEH.


Therefore length GH is;


(GH)² = 1.61803398875²+1.61803398875²-2*1.61803398875*1.61803398875cos72


GH = 1.90211303259 units.


It implies;


GH/HI is;


1.90211303259/0.9510565163


= 2

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