Calculating Alpha.
Let it be x.
Let 1 unit be the equal lengths of the ascribed right-angled triangle each.
a² = 1²+1²
a = √(2) units.
a is AC.
b = 45-15
b = 30°
b is angle CAD.
c = 180-30-15
c = 135°
c is angle ADC.
(d/sin30) = (√(2)/sin135)
d = 1 unit.
d is CD.
It implies, triangle BCD is isosceles.
Therefore, Alph (x) angle BDC is;
x = ½(180-30)
x = ½(150)
x = 75°
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