Calculating x (AD).
a = 6-5
a = 1 unit.
tanb = 3/1
b = 71.5650511771°
Notice.
b is angle theta (angle ADC = angle BAD).
c = (180-b)+(90-b)
c = (180-71.5650511771)+(90-71.5650511771)
c = 126.869897646°
c is angle ABC.
d² = 3²+5²-2*3*5cos126.869897646
d = 7.21110255093 units.
d is AC.
(7.21110255093/sin126.869897646) = (5/sine)
e = 33.6900675259°
e is angle ACB.
f = 90-e
f = 90-33.6900675259
f = 56.3099324741°
f is angle ACD.
It implies, length x is;
(x/sin56.3099324741) = (7.21110255093/sin71.5650511771)
x = 6.32455532034 units.
Again, x is length AD.
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