Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
17th August, 2026

Calculating x (AD).


a = 6-5

a = 1 unit.


tanb = 3/1

b = 71.5650511771°


Notice.


b is angle theta (angle ADC = angle BAD).


c = (180-b)+(90-b)

c = (180-71.5650511771)+(90-71.5650511771)

c = 126.869897646°

c is angle ABC.


d² = 3²+5²-2*3*5cos126.869897646

d = 7.21110255093 units.

d is AC.


(7.21110255093/sin126.869897646) = (5/sine)

e = 33.6900675259°

e is angle ACB.


f = 90-e

f = 90-33.6900675259

f = 56.3099324741°

f is angle ACD.


It implies, length x is;


(x/sin56.3099324741) = (7.21110255093/sin71.5650511771)


x = 6.32455532034 units.

Again, x is length AD.

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