Mathematics Question and Solution
Calculating length c.
d = a+b
d = 8+9
d = 17 units.
e = b-a
e = 9-8
e = 1 unit.
It implies;
e²+f² = 17²
f² = 289-1
f = √(288)
f = 12√(2) units.
cosg = 1/17
g = acos(1/17)
g = 86.6277133166°
h = 180-g
h = 180-86.6277133166
h = 93.3722866834°
j = ½(g)
j = ½(86.6277133166)
j = 43.3138566583°
k = ½(h)
k = ½(93.3722866834)
k = 46.6861433417°
Therefore, length c is;
tan43.3138566583 = c/9
c = 9tan43.3138566583
c = 8.48528137424 units.
Or
tan46.6861433417 = c/8
c = 8tan46.6861433417
c = 8.48528137423 units.
Or
c = ½(f)
c = ½(12√(2))
c = 6√(2) units.
c = 8.48528137424 units.
