Calculating x, the base of the ascribed right-angled triangle.
a² = 15²+x²
a = √(15²+x²) units.
a is the hypotenuse of the ascribed right-angled triangle.
Therefore, x is;
3*15+3*x +3√(15²+x²) = 15*3
45+3x+3√(15²+x²) = 15x
3√(15²+x²) = 12x-45
9(225+x²) = 144x²-1080x+2025
2025+9x² = 144x²-1080x+2025
135x² = 1080x
135x = 1080
x = 1080/135
x = 8 units.
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