Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
26th July, 2025

Calculating Shaded Green Area.


sin30 = a/2

a = 1 unit.


(a')²+1² = 2²

a' = √(4-1)

a' = √(3) units.


a'' = 2a'

a'' = 2√(3) units.

a'' is the side length of the inscribed regular triangle.


b² = 2²+2²-2*2*2cos30

b² = 8-8cos30

b = 1.03527618041 units.


c²+a² = b²

c² = 1.03527618041²-1²

c = 0.26794919243 units.


d = 2c

d = 2*0.26794919243 

d = 0.53589838486 units.


Shaded Green Area is;


Area quarter circle with radius 2 units+Area equilateral triangle with side length 2√(3) units-3(area triangle with height 1 unit and base 0.53589838486)-6(area sector with radius 2 units and angle 30°)+6(area triangle with height 2 units and base 2sin30 units).


= ¼(π*2²)+½(2√(3))²sin60-3*½(0.53589838486*1)-6(30π*2²/360)+6(½*2²sin30)


= π+3√(3)-0.80384757729-6.28318530718+6


= π+3√(3)-1.08703288447


= 8.3377450763-1.08703288447


= 7.25071219183 square units.


= 7.25 square units to 2 decimal places.

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