Let a be the radius of the circle.
b² = 2(2)²
b = √(8)
b = 2√(2) cm.
c = (2√(2)-a) cm.
It implies;
2a² = c²
2a² = (2√(2)-a)²
2a² = 8-4√(2)a+a²
a²+4√(2)a-8 = 0
(a+2√(2))² = 8+(2√(2))²
(a+2√(2))² = 16
a = -2√(2)±√(16)
a = -2√(2)±4
Therefore;
a = (4-2√(2)) cm.
Area inscribed circle is;
πa²
= π(4-2√(2))²
= π(16-16√(2)+8)
= 8π(3-2√(2)) cm²
= 4.31209667562 cm²
We appreciate you contacting us. Our support will get back in touch with you soon!
Have a great day!
Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support