Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
31st May, 2025

Calculating area of the red inscribed circle.


Let a be the radius of the blue ascribed circle.


πa² =144π

a² = 144

a = 12 cm.


b = 2a

b = 24 cm.

b is the diameter of the blue ascribed circle.


2c² = 24²

c² = 12*24

c = 12√(2) cm.

c is the side length of the inscribed square.


Let y be the radius of the red inscribed circle.


d = 2y cm.

d is the diameter of the red inscribed circle.


2e² = (2y)²

e² = 2y²

e = √(2)y cm.


f = ½(e) 

f = ½√(2)y cm.


g = 12√(2)-f

g = ½(24√(2)-√(2)y) cm.


h = ½(12√(2))-½√(2)y

h = ½(12√(2)-√(2)y) cm.


j = (6√(2)+y) cm.


Calculating y.


(6√(2)+y)² = (½(12√(2)-√(2)y))²+(½(24√(2)-√(2)y))²


72+12√(2)y+y² = ¼(288-48y+2y²)+¼(1152-96y+2y²)

288+48√(2)y+4y² = 288-48y+2y²+1152-96y+2y²

48√(2)y+4y² = 4y²-144y+1152

48√(2)y = 1152-144y

6√(2)y = 144-18y

2√(2)y = 72-9y

(2√(2)+9)y = 72

y = 72/(2√(2)+9)

y = 6.08703078107 units.

Again, x is the radius of the red inscribed circle.


Therefore, area red circle is;


πy²

= π(6.08703078107)²

= 116.402114222 cm²


Calculating cosx.


Recall.


j = (6√(2)+y)

And y = 6.08703078107 cm.

j = 14.5723121553 cm.


Recall Again.


h = ½(12√(2)-√(2)y)

And y = 6.08703078107 cm.

h = ½(12√(2)-√(2)*6.08703078107)

h = 4.18110063165 cm.


Therefore;


cosx = h/j

cosx = (4.18110063165/14.5723121553)

cosx = 0.2869208803

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