Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
10th May, 2025

Radius R of the big circle is 50 unit.

(R-10)²=R(R-18)

R²-20R+100=R²-18R

2R=100

R=50 units.


Radius r of the small inscribed unshaded circle is 41 unit.

2r=2R-18, and R=50

2r=100-18

2r=82

r=41 units.


Therefore shaded area will be;


50²π - 41²π


= 819π square units.

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