The radius of the circle with the inscribed square will be;
½(√(4²+4²))
= ½(√(32))
= ½(4√(2))
= 2√(2) cm.
Therefore Blue Area will be;
2(area circle of radius 2cm) - area circle of radius 2√(2)cm + area square of single side length 4cm.
It will be;
2(2²π) - ((2√(2))²π) +(4x4)
= 8π - 8π + 16
= 16 cm²
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