Sir Mike Ambrose is the author of the question.
Let the side length of the three congruent, inscribed square be x.
Calculating x.
x + 2 = 2√(3)
x = (2√(3)-2) units.
Therefore;
Area green exactly in square units decimal form is;
Area triangle with height (2√(3)-2) units and base (4-2√(3)) units + Area triangle with height (2√(3)-2) units and base ⅓(6-2√(3)) units + Area triangle with height 1.55909609016 units and base ⅓(4√(3)-6)sin(50.103909361) units.
= (0.5*(2√(3)-2)(4-2√(3))) + (0.5*(2√(3)-2)*⅓(6-2√(3))) + (0.5*1.55909609016*⅓(4√(3)-6)sin(50.103909361))
= 0.39230484541 + 0.61880215352 + 0.18504542378
= 1.19615242271 square units.
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