Mathematics Question and Solution
Calculating angle x.
Let 1 be the base of the ascribed isosceles triangle.
a = 180-39-2(27)
a = 141-54
a = 87°
(1/sin87) = (b/sin(2*27))
b = 0.8101272456 units.
c = 180-27-15-39
c = 180-81
c = 99°
(1/sin99) = (d/sin27)
d = 0.4596495484 units.
e² = 0.4596495484²+0.8101272456²-2*0.4596495484*0.8101272456cos15
e = 0.3849822481 units.
It implies, the required angle x is;
(0.3849822481/sin15) = (0.4596495484/sinx)
x = 18°
