Mathematics Question and Solution
Calculating angle x.
Let BC be 2 units.
a = 180-70-40
a = 70°
a is angle ACB.
cos70 = 1/b
b = 2.9238044002 units.
b is AB.
c = 180-80-50
c = 50°
c is angle ADC.
d = ½(b)
d = 1.4619022001 units.
d is AY = DY.
cos50 = e/2.9238044002
e = 1.8793852416 units
e is CX = DX.
f² = 1²+1.8793852416²-2*1*1.8793852416cos(70+50)
f = 2.5320888863 units.
f is MX.
(2.5320888863/sin120) = (1/sing)
g = 20°
g is angle CXM.
h² = 1.8793852416²+1.4619022001²-2*1.4619022001*1.8793852416cos50
h = 1.4619022001 units.
h is XY.
(1.4619022001/sin50) = (1.4619022001/sinj)
j = 50°
j is angle DXY.
Therefore, the required angle x, angle MXY is;
x = 180-g-j
x = 180-20-50
x = 110°
Again, x the required angle is angle MXY.
