Let the base of the inscribed green triangle be a.
b = (8-a) units.
c² = a²+8²
c = √(a²+64) units.
It implies;
(8-a)+8 = √(a²+64)
(16-a)² = a²+64
256-32a+a² = a²+64
32a = 192
4a = 24
a = 6 units.
Therefore, area green inscribed triangle is;
½*a*8
= ½*6*8
= 24 square units.
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