Let a be the radius of the half circle.
b = (a-2) cm.
It implies, calculating a.
a² = 4²+(a-2)²
a² = 16+a²-4a+4
4a = 20
a = 5 cm.
Again, a is the radius of the half circle.
Therefore;
b = (a-2)
And a = 5 cm.
b = 5-2
b = 3 cm.
tanc = 4/3
c = atan(4/3)°
Area blue is;
Area sector with radius 5 cm and angle atan(4/3)° - Area triangle with height and base 4 cm and 3 cm respectively.
(atan(4/3)π*5*5/360)-½(4*3)
= 11.591190225-6
= 5.591190225 cm²
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