Mathematics Question and Solution
Calculating yellow inscribed triangle area.
It implies;
Calculating a, the inscribed triangle opposite the short length of the ascribed triangle.
36+0.5*8*3sina = 0.5*(8+3)*(4+8)Sina
a is thr
36+12sina = 66sina
36 = 66sina-12sina
54sina = 36
sina = 36/54
sina = 2/3
a = asin(2/3)
a = 41.8103148958°
Therefore, the required area, yellow inscribed triangle area is;
0.5*3*8sin41.8103148958
= 8 square units.
