Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
28th July, 2024

7² = 3²+5²-2*3*5cosa

49 = 34-30cosa

cosa = (34-49)/30

a = acos(-15/30

a = 120°

a is angle ADC.


b = 180-a

b = 60°

b is angle ADB.


Therefore, the required angle, angle ABC is;


Let it be c.


c+70+60 = 180

c = 180-60-70

c = 180-130

c = 50°

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