Let the radius of the quarter circle be a.
b = (a-4) units.
c = (a-2) units.
It implies;
a² = (a-4)²+(a-2)²
a² = a²-8a+16+a²-4a+4
a²-12a+20 = 0
a²-2a-10a+20 = 0
a(a-2)-10(a-2) = 0
(a-2)(a-10) = 0
It implies;
a = 10 units.
Again, a is the radius of the quarter circle.
Therefore, area quarter circle is;
¼*10*10π
= 25π square units.
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