Mathematics Question and Solution
Sir Mike Ambrose is the author of the question.
Notice!
AB = BC
Calculating AB.
AB = (20sin60)/sin104
AB = BC = 17.85075169007 cm.
Calculating BD
BD = (20sin16)/sin104
BD = 5.68151231326 cm.
Calculating CE.
CE = (17.85075169007sin44)/sin60
CE = 14.31848768674 cm.
Therefore;
Half DE is;
½(CE=DE)
= ½(14.31848768674)
= 7.15924384337 cm.
It implies;
Area Blue (Big) is;
Area triangle with height 7.41361402363 cm and base 7.15924384337 cm.
= ½(7.15924384337*7.41361402363)
= 26.53793527789 cm²
Area Blue (Small) is;
Area triangle with height 2.59375780702 cm and base (4.98656005686sin44) cm.
= ½*(4.98656005686sin44)*2.59375780702
= 4.49233104836 cm²
Area Blue Total in cm² to 2 decimal places is;
4.49233104836 + 26.53793527789
= 31.03026632625 cm²
≈ 31.03 cm²
