Mathematics Question and Solution
a = 180-30-33
a = 117°
b+117+15+33+30+39 = 360
b = 360-180-54
b = 126°
c+126+30+9+39+57 = 360
c = 99°
d = 180-99-9
d = 180-108
d = 72°
e = a-57
e = 117-57
e = 60°
f = 180-60-33
f = 87°
g = 180-f
g = 93°
(1/sin33)/(h/sin60)
h = 1.5900905886 units.
j = 180-15-93
j = 72°
(1.5900905886/sin72) = (k/sin93)
k = 1.6696288786 units.
(1/sin30) = (l/sin57)
l = 1.6773411359 units.
m = h+l
m = 1.5900905886+1.6773411359
m = 3.2674317245 units.
(3.2674317245/sin39) = (n/sin126)
n = 4.2004165615 units.
o = n-k
o = 4.2004165615-1.6696288786
o = 2.5307876829 units.
(2.5307876829/sin99) = (p/sin72)
p = 2.4369247042 units.
q² = 2.4369247041²+4.2004165615²-2*2.4369247041*4.2004165615cos9
q = 1.833562177 units.
Therefore, the required angle x is;
(1.833562177/sin9) = (2.4369247042/sinx)
x = 12°
Again, the required angle x is;
x = 12°
