Mathematics Question and Solution
a²+1.5² = 4²
a² = 16-2.25
a = 3.7080992435 units.
tanb = a/1.5
b = atan(3.7080992435/1.5)
b = 67.9756871627°
b is angle ODC.
c = 90-b
c = 22.0243128373°
c is angle ODT.
It implies;
d² = 2²+4²-2*2*4cos22.0243128373
d = 2.2732362451 units.
d is OT.
Therefore, the required angle, alpha is;
Let it be f.
(2.2732362451/sin22.0243128373) = (4/sine)
e = 41.2886037973°
f = 180-e
f = 138.7113962027°
f is the required angle alpha.
Or
(2/sing) = (2.2732362451/sin22.0243128373)
g = 19.2642909605°
Therefore f is;
f = 180-g-c
f = 180-19.2642909605-22.0243128373
f = 138.7113962022°
Again, f is the required angle alpha.
