Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
17th March, 2024

Calculating the shaded area.


a² = 4²+6²-2*4*6cos30

a = 3.2296719057 units.


sin15 = b/6

b = 1.5529142706 units.


c = 90-15

c = 75°


Or


cosc = 1.5529142706/6

c = acos(1.5529142706/6)

c = 75°


(3.2296719057/sin30) = (4/sind)

d = 38.2619661994°


e = c-d

e = 75-38.2619661994

e = 36.7380338006°


tan36.7380338006 = f/1.5529142706

f = 1.1591109915 units.


Therefore, area shaded is;


Area triangle with height 1.5529142706 units and base 3.2296719057sin36.7380338006 units - Area triangle with height 1.1591109915 units and base 1.5529142706 units.


= (0.5*1.5529142706*3.2296719057sin36.7380338006)-(0.5*1.1591109915*1.5529142706)

= 1.5-0.9

= 0.6 square units.

= (3/5) square units.

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