Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
23rd May, 2024

cos30 = a/16

a = 8√(3) cm.


cos30 = 10/b

b = ⅓(20√(3)) cm.


c = a-b

c = 8√(3)-⅓(20√(3))

c = ⅓(4√(3)) units.


d = 2c

d = ⅓(2√(3)) cm.


e = b+d

e = ⅓(20√(3))+⅓(2√(3))

e = ⅓(22√(3)) cm 

e = 12.7017059222 cm.


f² = 12.7017059222²+8²-16*12.7017059222cos30

f = 7.0237691686 cm.


(7.0237691686/sin30) = (8/sing)

g = 34.7150039538°


h = 180-120-g

h = 25.2849960462°


tan25.2849960462 = 2/j

j = 4.233901974 units.


tan30 = k/10

k = ⅓(10√(3)) cm.


l = k-j

l = 1.5396007179 cm.


Area red is;


0.5*1.5396007179*⅓(2√(3))sin120

= 0.769800359 cm²


Area yellow is;


(0.5*12.7017059222*8sin30) - Area Red

= (0.5*12.7017059222*8sin30)-0.769800359

= 24.6336114854 cm²


It implies;


Area yellow ÷ Area red is;

24.6336114854÷0.769800359

= 31.9999999966

= 32

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