Calculating angle x.
Let the base of the ascribed triangle be 1 unit.
a = 180-20-10-10-100
a = 180-140
a = 40°
(1/sin(100+10)) = (b/sin40)
b = 0.6840402867 units.
c = 180-100-20
c = 60°
(0.6840402867/sin60) = (d/sin100)
d = 0.7778619134 units.
e² = 0.7778619134²+1-2*0.7778619134cos10
e = 0.2701486075 units.
(0.2701486075/sin10) = (0.7778619134/sinf)
f = 30°
It implies, the required angle x, is;
x+f = a
x+30 = 40
x = 40-30
x = 10°
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