a = 180-60
a = 120°
b² = 4²+6²-2*4*6cos120
b = 2√(19) units.
b = 8.7177978871 units.
b is the side length of the inscribed regular triangle ABC (equilateral triangle).
(8.7177978871/sin120) = (4/sinc)
c = 23.4132244464°
d = 60+c
d = 83.4132244464°
Therefore, length BD is;
(BD)² = 6²+8.7177978871²-2*6*8.7177978871cos83.4132244464
BD = 10 units.
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