Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
20th April, 2024

sin60 = 18/a

a = 20.7846096908 units.


tan60 = 18/b

b = 10.3923048454 units.


c+270+60+30+135 = 180(5-2)

c = 540-495

c = 45°


d² = 2(18²)

d = 18√(2) units.

d = 25.4558441227 units.


e = a+d

e = 20.7846096908+25.4558441227

e = 46.2404538135 units.


f = (85+z) units.

f is the required length x.

Therefore:

x = f = (85+z) units.


g = (46.2404538135+z) units.


tan60 = h/a

h = 20.7846096908tan60

h = 36 units.


j = (25.4558441227+z) units.

j is the required length y.

y = j = (25.4558441227+z) units.


k = f-h

k = (85+z)-36

k = (49+z) units.


Observing the side length ratios of similar right-angled triangles.


20.7846096908 - (25.4558441227+z)

                          36 - (49+z)

Cross Multiply.

20.7846096908(49+z) = 36(25.4558441227+z)

20.7846096908z+1018.4458748492 = 36z+916.4103884172

15.2153903092z = 102.035486432

z = 6.7060709163 units.


Therefore, required length x is;


x = f = (85+z)

And z = 6.7060709163 units.

x = 85+6.7060709163

x = 91.7060709163 units.


Therefore, required length y is;


y = j = (25.4558441227+z)

And z = 6.7060709163 units.

y = 25.4558441227+6.7060709163

y = 32.161915039 units.

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