a = ½(4+6)
a = 5 cm.
a is the radius of the ascribed semi circle.
Let b be the radius of the blue inscribed semi circle.
c = 5-4
c = 1 cm.
It implies;
b²+c² = d²
d² = b²+1²
d = √(b²+1) cm.
Therefore, calculate b, radius of the blue inscribed semi circle.
5² = d²+b²
25 = √(b²+1)²+b²
25 = 2b²+1
2b² = 24
b = √(12)
b = 2√(3) cm.
It implies, area blue is;
½(b)²π
= ½(2√(3))²π
= 6π square cm²
= 18.8495559215 cm²
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