a² = 6²-1²
a = √(35) units.
b = atan(√(35))
cos(atan(√(35))) = c/2
c = ⅓ unit.
Where c is CE.
d = atan(√(35))-60
d = 20.40593177314°
Where d is angle FCE.
tan20.40593177314 = e/(1/3)
e = 0.12400483955 units.
Where e is EF.
f = 6-(1/3)
f = ⅓(17) units.
Where f is AE.
Therefore;
Length AF is;
√((⅓(17))²+(0.12400483955)²)
= 5.66802331605 units.
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