Sir Mike Ambrose is the author of the question.
Aqua total in cm² is;
tan30 = a/10
a = ⅓(10√(3)) cm.
sin60 = 2/b
b = ⅓(4√(3)) cm.
c = a+b
c = ⅓(14√(3)) cm.
tan30 = d/2
d = ⅓(2√(3)) cm.
e = c-d
e = 4√(3) cm.
Where e is the side length of the green inscribed regular hexagon.
f = (120-atan(7√(3)/15))°
g² = c²+10²
g = ⅓(4√(93)) cm.
h = ⅔(√(3)) cm.
i = 6-htan60
i = 2 cm.
j = 6-i
j = 4 cm.
k² = h²+2²
k = ⅓(4√(3)) cm.
It implies;
Total Area Aqua exactly in cm² is;
Area triangle with height ⅓(14√(3)) cm and base 10 cm + area triangle with height ⅓(4√(93)) cm and base 2sin(120-atan(7√(3)/15)) cm + Area triangle with height 8 cm and base 8sin120 cm - Area triangle with height ⅓(4√(3)) cm and base ⅓(4√(3))sin120 cm
= ⅓(70√(3)) + ⅓(22√(3)) + 16√(3) - ⅓(4√(3))
= ⅓(88√(3) + 16√(3)
= ⅓(136√(3)) cm²
We appreciate you contacting us. Our support will get back in touch with you soon!
Have a great day!
Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support