a² =10²-6²
a = 8 cm.
tanb = 3/4
b = atan(3/4)°
(3/4) = c/10
c = ½(15) cm.
c = 7.5 cm.
sin(atan(3/4)) = d/8
d = 4.8 cm.
e = 7.5-4.8
e = 2.7 cm.
(3/4) = 2.7/f
f = 3.6 cm.
g² = 2.7²+3.6²
g = 4.5 cm.
h² = 10²-4.8²
h = ⅖√(481) cm.
h = 8.77268487978 cm.
j = ⅖√(481)-3.6
j = 8.77268487978-3.6
j = 5.17268487978 cm.
Or
j = ⅖√(481)-(18/5)
j = ⅕(2√(481)-18) cm.
k = (108-atan(¾))°
It implies;
Area Red Exactly is;
0.5*⅕(2√(481)-18)*4.5sin(180-atan(3/4))
= 27(√(481)-9)/50 cm²
= 6.98312458771 cm²
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