Mathematics Question and Solution
Let the radius of the 3 congruent circles be r.
Therefore, the general formula for the area of green section is;
½(πr²)-3(60πr²)/360+2(½*r²*sin60)
= ½(πr²)-½(πr²)+r²sin60
= r²sin60
= ½(√(3)r²) square units.
The green area does not rely on pie because it can be structured to two congruent equilateral triangles (plane shapes) with single side length r (radius) units each which is equal to the radius of each of the three congruent circles.
