Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
21st June, 2023

Let the radius of the ascribed circle be 2 units.


sin10 = a/2

a = 0.34729635533 units.

a is O1D.


cos10 = b/2

b = 1.96961550602 units.

b is CD.


Let the small inscribed circle radius be r.


Calculating r.


(2-r)² = r²+(0.34729635533+r)²


4-4r+r² = r²+0.12061475843+0.69459271066r+r²


r²+4.69459271066r-3.87938524157 = 0

It implies;

r = 0.716881 units.


c = 2-0.34729635533

c = 1.65270364467 units.

c is BD.


tand = 1.65270364467/1.96961550602

d = 40°

d is angle BCD.


tane = 0.716881/1.96961550602

e = 20°

e is angle DCP.


Therefore;


Angle PCB is;


d-e

= 40-20

= 20°

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